is a Stochastic
Process.
The process is in state i
at time n if
.
Unless otherwise mentioned,
.
Whenever the process is in state i, there is a fixed probability
that it will next be
in state j.
Let P be the
matrix of one-step transition probabilities
then
![]()
P = ![]()

, where
for all i.
Markov Chain: is a STOCHASTIC process such that the conditional distribution of any
future state is independent of the past states and depends ONLY on the
present state. That is,
![]()
1. Suppose that the chance of rain tomorrow depends on previous weather conditions only through whether or not it is raining today and not on past weather conditions. Suppose also that if it rains today, then it will rain tomorrow with probability a; and if it does not rain today, then it will rain tomorrow with probability b.
If we say that the process is in state 0 when it rains and state 1 when it does not rain, then the above is a two-state Markov chain. Express its matrix of transition probabilities.
2. A communications system transmits the digits 0 and 1.
Each digit transmitted must pass through several stages, at each of which there
is a probability p that the digit entered will be unchanged when it leaves.
Letting
denote the digit entering the nth stage, then
is a two-state Markov chain. Express its matrix of
transition probabilities.
3. On a given day, Gary is either cheerful (C), so-so (S), or glum (G). If he is cheerful today, then he will be C, S, or G tomorrow with respective probabilities 0.5, 0.4, 0.1. If he is feeling so-so today, then he will be C, S, or G tomorrow with probabilities 0.3, 0.4, 0.3. If he is glum today, then he will be C, S, or G tomorrow with probabilities 0.2, 0.3, 0.5.
Letting
denote Gary’s mood on the n-th day, then
is a three-state Markov chain (state 0 = C, state 1 = S,
state 2 = G). Express its matrix of transition probabilities.
4. A Markov chain whose state space is given by integers i = 0, ±1, ±2, … is called a random walk if, for some number 0 < p < 1,
,
, i = 0, ±1, ±2,
…
Remark: We may consider a random walk as a model for a person walking on a straight
line who at each point of time either takes one step to the right with probability
p or one step to the left with probability 1-p.
5. Consider a gambler who, at each play of the game, either wins $1 with probability p or loses $1 with probability 1-p.
If we suppose that our gambler quits playing either when he goes broke or he attains a fortune of $N, then the gambler’s fortune is a Markov chain having transition probabilities
,
, i = 0, ±1, ±2, …
![]()
States 0 and N are called absorbing states since once entered they are never left.
We define the
n-step transition
probabilities
: n ³ 0, i, j
³
0
= P( a process in state i will be in state j after n additional transitions)
= P![]()
Chapman-Kolmogorov Equations:
for all n, m ³ 0, all i, j
Remark: The above C-K equations provide a method for computing n-step transition
probabilities
.
Let P (n)
be the matrix of n-step transition
probabilities
, then Chapman-Kolmogorov Equations give us:
P (n+m) = P (n) ×P (m)
As a result, P (n) = P (n-1)×P (1)
= P×P×P×P×××P
= P n
1. If the one-step transition probability matrix is given by
P =
, find P (4)
and
.
2. Given the transition probability matrix with states 0 and 1
P =
, find
a)
the probability
that it will be in state 1 after 4 transition given that it is in state 0 now.
b)
P(
) if P(
) = 0.4 and P(
) = 0.6.
Remark:
are conditional
probabilities. It is necessary to specify the probability distribution of
the initial state in order to obtain the unconditional probability
distribution of the state at time, say n.
3.
State 0 if it rained both today and yesterday
State 1 if it rained today but not yesterday
State 2 if it rained yesterday but not today
State 3 if it did not rain either yesterday or today
Basing on a four-state Markov Chain having the following transition probability matrix
P =
, given that it rained on Monday and Tuesday, what is the
probability that it will rain on Thursday?
Math 413 Markov Chains(3) Winter 2002
The state j is accessible
from state i if and only if, starting
in i, it is possible that the process will ever enter state j. That is
>0 for some n ³ 0.
Two states i and j are said to communicate if they are accessible to each other.
We write
i
j
Three properties for communication:
1. State i communicates with state i, all i ³ 0.
2. If state i communicates with state j, then state j communicate with state i.
3. If state i communicates with state i, and state j communicates with state k, then state i communicates with state k.
Class: Two states that communicate are said to be in the same class.
Any two classes of states are either identical or disjoint. (why?)
Communication divides the state space up into a number of separate classes.
Irreducible: The Markov chain is said to be irreducible if there is only one class. (All states communicate with each other.)
1.
Is this Markov chain irreducible? Verify.
2.
Is this Markov chain irreducible? Verify.
State i is said to be recurrent if
=1 (
is the probability that, starting in state i, the process
will ever reenter state i.)
State i is said to be transient if
<1.
Propositions:
1.
State i is recurrent if
.
2.
State i is transient if
.
3. If state i is recurrent, and state j communicates with state i, then state j is recurrent.
4. If state i is transient and communicates with state j, then state j is transient.
5. All states of a finite irreducible Markov chain are recurrent.
1. Determine which states are transient and which are recurrent.

2. Determine which states are transient and which are recurrent.

3. For a random walk,
, i = 0, ±1, ±2, …
Which states are recurrent?
4. Compute the probability of whether the one-dimensional random walk ever returns to state 0 when p¹1/2.
5. Consider a communications facility in which the numbers
of messages arriving during each of the time periods n = 1, 2, … are
independent and identically distributed random variables. Let
and suppose that
Each arriving message will transmit at the end of the period
in which it arrives. If exactly one message is transmitted, then the
transmission is successful and the message leaves the system. However, if at
any time two or more messages simultaneously transmit, then a collision is
deemed to occur and these messages remain in the system. Once a message is
involved in a collision it will, independently of all else, transmit at the end
of each additional period with probability p
(--called Aloha protocol)
Such a system is asymptotically unstable in the sense that the number of successful transmissions will, with PROBABILITY 1, be FINITE.
Math 413 Markov Chains(4) Winter 2002
In some cases,
is converging to some value as
. The value is the same for all i.
That is, all the rows of the matrix
are the same as
.
This is the limiting probability that he process will be in state j after a large number of transitions, and the probability is independent of the initial state i.
Period
State i is said to have period d if
whenever n is not
divisible by d, and d is the largest integer with this property.
Periodicity is a class property. If state I has period d, and states i and j communicate, then state j also has period d.
Aperiodic
A state with period 1 is said to be aperiodic.
Positive
Recurrent
State i is said to be positive recurrent if it is recurrent and if, starting in i, the expected time until the process returns to state i is finite.
In a finite-state Markov chain all recurrent states are positive recurrent.
Ergodic
Positive recurrent, aperiodic states are called ergodic.
Theorem
For an irreducible ergodic Markov
chain
exists and is independent of i.
Furthermore, letting
, then
is the unique
solution of 
Remark 1:
The long run proportions
, are called stationary probabilities. If the
initial state is chosen according to the probabilities
, then the probability of being in state j at any time
n is equal to
.
In other words, if
then
for all n, j
0.
Remark 2:
Let
be the expected number of transitions until a Markov chain
starting in state j, returns to that state.
It follows that
(on average,
the process will spend 1 unit of time in state j for every
units of time.)
1. In Ellensburg, if it rains today, then it will rain tomorrow with probability a; and if it does not rain today, then it will rain tomorrow with probability b. If we say that the state is 0 when it rains and 1 when it does not rain, then
(a)
find
and
.
(b) find the limiting probability of rain when a=0.7 and b=0.4.
2. Suppose the mood of an individual is considered as a three-state Markov chain having a transition probability matrix
P
=
.
In the long run, what proportion of time is the process in each of the three states?
3. A problem of interest to sociologists is to determine the proportion of society that has an upper- or lower-class occupation. One possible mathematical model would be to assume that transitions between social classes of the successive generations in a family can be regarded as transitions of a Markov chain. That is, we assume that the occupation of a child depends only on his or her parent’s occupation. Let us suppose that such a model is appropriate and that the transition probability matrix is given by
P
=
.
That is, the child of a middle-class worker will attain an upper-, middle, or lower-class occupation with respective probabilities 0.05, 0.70, 0.25.
In the long run, what percent of people are in upper-class jobs? Middle-class jobs? Lower-class jobs?
4. Suppose that the Coca Cola production process changes states in accordance with a Markov chain having the following transition probability matrix.

Suppose that the acceptable states are 0, 1 (up) and the unacceptable
states are 2, 3 (down). Determine
a)
the rate at
which the production process goes from up to down.
b)
The average
length of time the process remains down when it goes down.
c)
The average
length of time the process remains up when it goes up
Math 413 Markov Chains(5) Winter 2002
The
Gambler’s Ruin Problem
1. Suppose that Sean plays a game and at each play of the game he has probability p of winning one dollar and probability 1-p of losing one dollar. Assuming that successive plays of the game are independent and Sean will stop playing if he lost all his money or his fortune reaches $7 , what is the probability that, starting with 2 dollars, Sean’s fortune will reach 7 dollars before reaching 0?
2. Suppose that Jon and Rocklyn decide to flip pennies; the one coming
closest to the wall wins. Jon, being the better player, has a probability of
0.6 of winning on each flip.
a)
If Jon starts
with 5 pennies and Rocklyn with 10, then what is the probability that Jon will
wipe Rocklyn out?
b)
What if Jon
starts with 10 and Rocklyn with 20?
3. Continued from the first problem, supposed that Sean will win each play with probability 0.4 and he will quit if he lost all the money or reach $7.
a) find the expected amount of time Sean has 5 dollars.
b) find the expected amount of time Sean has 2 dollars.